I curious as to what version of j64 you are using. Are the COM servers
still embedded in j8.02?
Yes, they are. :)
On Mon, Aug 18, 2014 at 7:55 AM, bill lam <[email protected]> wrote:
I'm not an expert on C#, but it seems that int is always 4-byte
whether on
32 or 64 bit, so that you propably need int64[] for J64.
On Aug 18, 2014 8:16 PM, <[email protected]> wrote:
> I have an issue with the 64-bit JDLLServer in relation to 64
integers. It
> seems that JDLLServer handles only the lower 32 bits of a 64 bit
value.
The
> following test demonstrates this issue:
>
> Test (C#):
> var value = 1000 + ((Int64)1 << 32);
> _j.Do(String.Format("a =: {0}", value));
> Assert.AreEqual(value, _j.GetB("a"));
>
> Results:
> Assert.AreEqual failed. Expected:<4294968296 (System.Int64)>.
Actual:<1000
> (System.Int32)>.
>
>
> There is a similar problem to getting int arrays. The following
test
fails:
>
> _j.Do("a =: 10 20 30");
>
> var a = (int[])_j.GetB("a");
> Assert.AreEqual(10, a[0]);
> Assert.AreEqual(20, a[1]);
> Assert.AreEqual(30, a[2]);
>
> The result of 'a' is not '10 20 30', but '10 0 20'. I guess, '0'
stands
> for the higher 32 bits of the whole value '10 0'.
>
> What can I do to resolve these issues?
> I can not switch to the 32 bit J version, because I work with JD,
that
> requires a 64 bit J.
> My current workaround is avoiding integers and only work with
floats, but
> this is not a real solution.
>
> Any Ideas?
>
> PS: Sorry for my English :)
>
>
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--
John D. Baker
[email protected]
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