Todayno comes from name_z_ '' It is quite charming. IT provides the number of days there are between 1800 1 1 and and in this case 2014 9 20. Tomorrow the number will increase by one.
My groundhog was born on 2002 2 2 How old is he? Maybe this will be closer to what I should be writing. I probably be missing the mark if you can't read it and understand it. I shall try to simplify further. Linda -----Original Message----- From: [email protected] [mailto:[email protected]] On Behalf Of Raul Miller Sent: Saturday, September 20, 2014 12:24 PM To: Programming forum Subject: Re: [Jprogramming] Weekend Puzzle - Age of Groundhog born 2002 2 2 Not being a child, I originally stopped reading at todayno 2014 9 2014 because that sentence did not make sense to me. And once that happens, code ceases to be interesting for me. I also must admit to being baffled by the later requirements. That said, age=: - would work for your stated problem and for some people's birthdays (including mine). Actually, without some way of checking the results, I doubt many children could distinguish between that solution and a correct solution. Anyways, I'm going to confess puzzlement at your approach. Thanks, -- Raul On Sat, Sep 20, 2014 at 11:54 AM, Linda Alvord <[email protected]> wrote: > We are talking children here. > > Onyadot. emiTetaDot, ffiDst, onyadot, emiTetaDot, emitetad, sepyt and > eriuqer are all denied! > > How about using +, -, *, ?, %: and that sort of thing. > > I must admit you did get the right answer! > > You can also get a second chance. > > Cheers, Linda > > > > -----Original Message----- > From: [email protected] > [mailto:[email protected]] On Behalf Of Joe Bogner > Sent: Saturday, September 20, 2014 9:10 AM > To: [email protected] > Subject: Re: [Jprogramming] Weekend Puzzle - Age of Groundhog born 2002 2 2 > > solution... > > > > > > > 1 > 2 > 3 > 4 > 5 > > > lightly obfuscated for someone who doesn't want the solution > > > solution1=: 0 : 0 > > )2 2 2002 onyadot emiTetaDot( ffiDst )02 9 4102 onyadot emiTetaDot( > > 'emitetad/sepyt' eriuqer > > ) > > > > to run: > > > 0!:1 |. solution1 > > > > solution2 =: 0 : 0 > > )2 2 2002( ffiDst )02 9 4102( > > 'emitetad/sepyt' eriuqer > > ) > > > 0!:1 |. solution2 > > > > note: both take advantage of a addon. solution1 uses todayno just because > it was stated in the problem but solution2 is what I'd really use > > > > On Sat, Sep 20, 2014 at 4:54 AM, Linda Alvord <[email protected]> > wrote: > >> Using the verb todayno which provides the number of days since the >> beginning of 1800, write what you need to find the age today of a >> groundhog >> born on 2002 2 2. >> >> >> >> todayno 2014 9 2014 >> >> 80418 >> >> >> >> 2014 9 20 age 2002 2 2 >> >> 12 7 18 >> >> >> >> His age is 12 years, 7 months and 18 days. Use simple J. Check that your >> solution provides a correct answer for you birthday. >> >> >> >> Have a pleasant weekend. >> >> >> >> Linda >> >> >> >> >> >> >> >> >> >> >> >> >> >> >> >> ---------------------------------------------------------------------- >> For information about J forums see http://www.jsoftware.com/forums.htm >> > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
