Hello Jose, I understand you are applying this identity : x u&n y <--> u&n^:x y
But I cannot see the correct mapping in your expressions. I suppose this is an hook, so (u v) y --> y u v y 3 ((2x&*) &1) 3 ((2x&*) &1^:3 3 means repeat three times 2*1, i.e. 2*1*2*1*2*1 = 8 correct ? thanks, Fausto 2015-02-19 1:19 GMT+01:00 Henry Rich <[email protected]>: > If you're going to use dissect, get 3.6.42 (released today). Previous > versions had a confusing title for the verbs. > > Even with the picture it's amazing what this little phrase does. Two nested > powers, with the result of one power feeding back into the exponent of the > next iteration of the same verb. > > Henry Rich > > > On 2/18/2015 7:12 PM, Jose Mario Quintana wrote: >> >> ((2x&*) &1) 3 >> 8 >> ((2x&*)^:3) 1 >> 8 >> ((3x&*) &1) 2 >> 9 >> ((3x&*)^:2) 1 >> 9 >> >> >> Does dissect >> >> >> http://www.jsoftware.com/jwiki/action/show/Vocabulary/Dissect?action=show&redirect=Addons%2Fdebug%2Fdissect >> >> help to follow the execution of the sentences? >> >> >> >> >> ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
