Sorry I'm dense. I understand that. But the first polynomial is not
remotely related to the second other than the gcd of both is x-8. Why?
On Aug 8, 2015 8:08 PM, "'Pascal Jasmin' via Programming" <
[email protected]> wrote:

> (x-1)x(x+1) or x(x+1)(x+2) and their expansions are algebraic solutions to
> special products.  All the solutions posted used one of these 2 forms.
> (your example uses the 2nd's expansion)
>
>
> ----- Original Message -----
> From: Don Guinn <[email protected]>
> To: Programming forum <[email protected]>
> Cc:
> Sent: Saturday, August 8, 2015 9:53 PM
> Subject: Re: [Jprogramming] Detecting special products
>
> ​Using polynomials to solve this problem is really neat, but why does it
> work? I can't find anything on the internet explaining why it works.
>
>    p._720 2 3 1
> +-+----------------------------+
> |1|_5.5j7.72981 _5.5j_7.72981 8|
> +-+----------------------------+
>    p.1;-8 9 10
> 720 242 27 1
>
> Obviously the polynomial for the roots is quite different from that used
> above. There has to be a proof somewhere.​
>
> On Fri, Aug 7, 2015 at 9:47 PM, Don Kelly <[email protected]> wrote:
>
> > correction : 'will be the <last> number of the sequence'
> > in any case for a special number the real root will be an integer.
> >
> >
> > On 06/08/2015 4:06 PM, Don Kelly wrote:
> >
> >> also try
> >> 0=1|( <1; 2) {>p.|.1 3 2,-]720
> >>
> >> 1_
> >>
> >> 0=1|( <1; 2) {>p.|.1 3 2,-]719
> >>
> >> 0
> >>
> >>  note that
> >> (<1;2) {>p._y 2 3 1
> >> will return an integer for a special number and this will be the first
> >> number of the sequence
> >> based on x*x+1)*(x+2) -y=0 giving an integral root
> >> p._720 2 3 1
> >>
> >> ┌─┬────────────────────────────┐
> >>
> >> │1│_5.5j7.72981 _5.5j_7.72981 8│
> >>
> >> └─┴────────────────────────────┘
> >>
> >>
> >> a modification to x(x^2-1) gives an integral real root for the middle
> root
> >> p. _720 _1 0 1
> >>
> >> ┌─┬────────────────────────────┐
> >>
> >> │1│9 _4.5j7.72981 _4.5j_7.72981│
> >>
> >> └─┴────────────────────────────┘
> >>
> >> puts the real root first rather than last
> >>
> >> As for finding a list of these special numbers-the "stope " function
> >> works well
> >> f=:3^!.1~[:i.]
> >>
> >> f 10
> >>
> >> 0 6 24 60 120 210 336 504 720 990
> >>
> >>
> >> Don Kelly
> >>
> >>
> >>
> >>
> >>
> >> On 06/08/2015 1:02 PM, Roger Hui wrote:
> >>
> >>>     g=: = (^&3 - ])@:(3&(>.@%:))
> >>>     g */"1 (10^40 60 80x)+/0 1 2
> >>> 1 1 1
> >>>
> >>>
> >>> On Thu, Aug 6, 2015 at 11:23 AM, 'Pascal Jasmin' via Programming <
> >>> [email protected]> wrote:
> >>>
> >>> (] = (^&3 - ])@:(1r3 >.@^~ ])) 990
> >>>>
> >>>>
> >>>>
> >>>> ----- Original Message -----
> >>>> From: Kip Murray <[email protected]>
> >>>> To: "[email protected]" <[email protected]>
> >>>> Cc:
> >>>> Sent: Thursday, August 6, 2015 1:58 PM
> >>>> Subject: [Jprogramming] Detecting special products
> >>>>
> >>>> The number  720  is  special: it is  8*9*10  the product of three
> >>>> successive non-negative integers.  The first few special numbers are
> >>>>
> >>>>      */"1 [ 0 1 2 +"1 0 i. 10
> >>>> 0 6 24 60 120 210 336 504 720 990
> >>>>
> >>>> Write a verb  test  that tests whether a non-negative integer is
> >>>> special:
> >>>>
> >>>>      test 720
> >>>> 1
> >>>>      test 0
> >>>> 1
> >>>>      test 721
> >>>> 0
> >>>>
> >>>> --Kip Murray
> >>>>
> >>>>
> >>>>
> >>>> --
> >>>> Sent from Gmail Mobile
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