Indeed lisL does return several results. I believe one verb I wrote returned
all subsequences of maximal length, but the (much faster) version which is
referred to by lisL only returns some longest subsequences. They should all be
correct.
Louis
> On 09 Sep 2016, at 17:04, Raul Miller <rauldmil...@gmail.com> wrote:
>
> Hmm... thinking that through,
>
> NB. longest sequence lengths should all match
> assert 1=#~.{:@$@>(lisI; lisJ; lisM; lisL; lisEH) a
>
> (And also could use a verification that each longest sequence is a valid
> one...)
>
> Thanks,
>
> --
> Raul
>
>
> On Fri, Sep 9, 2016 at 10:30 AM, Erling Hellenäs
> <erl...@erlinghellenas.se> wrote:
>> Hi all !
>>
>> Good point. It seems lisI gives strange results. lisL sometimes gives
>> several results, which are probably all correct. There can be many different
>> longest strictly increasing subsequences.
>>
>> a
>>
>> 4 12 10 23 18 19 8 7 5 2 0 16 15 11 1 9 22 3 13 14 21 17 24 20 6
>>
>> lisI a
>>
>> 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2
>> 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 3 3 3 4 4 4 5
>>
>> lisJ a
>>
>> 0 1 3 13 14 17 20
>>
>> lisM a
>>
>> 0 1 3 13 14 17 20
>>
>> lisL a
>>
>> 0 1 3 13 14 17 20
>>
>> 4 5 9 13 14 17 20
>>
>> lisXR a
>>
>> 0 1 3 13 14 17 20
>>
>> lisEH a
>>
>> 0 1 3 13 14 17 20
>>
>>
>> Cheers,
>> Erling
>>
>>
>>
>>> On 2016-09-09 16:02, Raul Miller wrote:
>>>
>>> 1=#~.(lisI; lisJ; lisM; lisL; lisEH) a
>>
>>
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