sumpears=: +/@]^:[&.>~ (*. 1 = +/\"1)@:(=/@>)

Does this do what you want?

Louis



Sent from my iPhone
> On 07 Nov 2016, at 05:50, Skip Cave <[email protected]> wrote:
> 
> NB. I have the following array n consisting of 5 identical rows of boxed
> pairs of integers:
> 
>  n
> 
> ┌───┬───┬───┬───┬───┬───┬───┬───┬───┬───┬───┬───┐
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│4 4│4 4│4 2│2 3│3 3│
> 
> ├───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┤
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│4 4│4 4│4 2│2 3│3 3│
> 
> ├───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┤
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│4 4│4 4│4 2│2 3│3 3│
> 
> ├───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┤
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│4 4│4 4│4 2│2 3│3 3│
> 
> ├───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┤
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│4 4│4 4│4 2│2 3│3 3│
> 
> └───┴───┴───┴───┴───┴───┴───┴───┴───┴───┴───┴───┘
> 
> 
> I want to design a verb f such that it will find boxes containing duplicate
> pairs in n. f will sum the duplicate pairs, and replace the duplicate with
> the sum of the two pairs. However, I want to do this only once for each row,
> 
> and find a new pair in the subsequent row to replace. See the result below.
> 
> f n
> 
> ┌───┬───┬───┬───┬───┬───┬───┬───┬───┬───┬───┬───┐
> 
> │1 2│ 4 │2 4│4 1│1 5│5 3│3 4│4 4│4 4│4 2│2 3│3 3│
> 
> ├───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┤
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│ 8 │4 4│4 2│2 3│3 3│
> 
> ├───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┤
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│4 4│ 8 │4 2│2 3│3 3│
> 
> ├───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┤
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│4 4│4 4│4 2│2 3│ 6 │
> 
> ├───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┼───┤
> 
> │1 2│2 2│2 4│4 1│1 5│5 3│3 4│4 4│4 4│4 2│2 3│3 3│
> 
> └───┴───┴───┴───┴───┴───┴───┴───┴───┴───┴───┴───┘
> 
> If all duplicates have been found, no change will be made in the row.
> 
> Can this be done without control statements?
> 
> 
> Skip
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