part 1 emits R, part 2 emits RB. RB parses the string in n argument with 1&p1 (which will emit RBs recursively)
the x argument of p1 determines whether its part 1(R) or part 2(RB) format. ----- Original Message ----- From: Brian Schott <[email protected]> To: Programming forum <[email protected]> Sent: Saturday, December 10, 2016 10:56 PM Subject: Re: [Jprogramming] AoC 2016 day 9 - Was Re: [Jbeta] possible memory leak j805 In this case is the verb you're binding ahead of, p1? You see I'm having trouble with RB because it both contains p1 and is contained in p1. And to be honest I don't see how the *dyad* p1 that is contained in RB gets its left argument (I figure x must equal 1 for RB to even be used in p1) but how does the p1 in RB know that? So, is p1 the verb you are trying to get ahead of, or is it just the verb do (".). Actually did you create RB and R only after you saw part 2? Thanks, On Sat, Dec 10, 2016 at 7:12 PM, 'Pascal Jasmin' via Programming < [email protected]> wrote: > a conjunction binds its (right) arguments ahead of a verb. it builds for > sample > > 0, 3 RB '(3x3)ABC(2x3)XY(5x2)PQRST',1, 9 RB '(3x2)TWO(5x7)SEVEN',0 > > and then I run this string with ". > > If it were a verb, I'd need parens around the verb arguments. > > > > > > > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
