Trying the patience of the forum here, but may I ask: were both parts
of the problem
visible all the time? After getting part one correct I started looking
for and found part
two below part one's submission area - either it was already there, or
else it was
revealed by the correct entry.
Anyway, when I did part one, I had no idea that there was a part two,
hence my silly remarks
(in J Beta) about there being no need for recursion.
Thanks,
Mike
On 11/12/2016 04:53, 'Pascal Jasmin' via Programming wrote:
I planned (and used) conjunctions for both parts to take advantage of the
binding preference of conjunctions. I'd need fewer parens.
4 (2 : 'm+n') 3 , 1
7 1
4 + 3 , 1
7 5
the conjunction executes before ,
It refers to the R or RB in the generated string/code.
----- Original Message -----
From: Brian Schott <[email protected]>
To: Programming forum <[email protected]>
Sent: Saturday, December 10, 2016 11:47 PM
Subject: Re: [Jprogramming] AoC 2016 day 9 - Was Re: [Jbeta] possible memory
leak j805
Yes, my bad. I was *blind* to the left-most 1 in the expression below.
(1 +/@:".@:}.@:p1 n)
But what about the rest of my questions:
a) When you first did part 1 did you use a conjunction, or was the
conjunction only needed in part 2, and so you revised part 1 to be similar?
b) And you state, "a conjunction binds its (right) arguments ahead of a
verb." Can you be specific about what verb you mean here. Is it the p1 that
is referred to inside of RB or some other verb?
By the way, I have considered putting my solution on the wiki as one NOT to
do because it is so inefficient it takes over 2 hours. You see, I
constructed all of the expanded strings and only counted their length after
all was computed. I think the time may have been exaggerated by all of the
disk swapping that must have been required. So I really was astonished by
the speed of your solution.
Thanks, again.
On Sat, Dec 10, 2016 at 11:29 PM, 'Pascal Jasmin' via Programming <
[email protected]> wrote:
part 1 emits R, part 2 emits RB. RB parses the string in n argument with
1&p1 (which will emit RBs recursively)
the x argument of p1 determines whether its part 1(R) or part 2(RB) format.
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