Eh... ok, but that's pretty hard to follow, and there's much simpler
ways of recognizing what's going on here.

-- 
Raul


On Mon, Feb 13, 2017 at 10:15 AM, Louis de Forcrand <[email protected]> wrote:
> I forgot to divide by m, see my correction.
>
> Louis
>
>> On 13 Feb 2017, at 15:24, Raul Miller <[email protected]> wrote:
>>
>> I'm having problems following your reasoning here.
>>
>> Consider:
>>
>>   A=: 5 3 $ 90 60 90 90 90 30 60 60 60 60 60 90 30 30 30
>>   mean=: +/%#
>>   mp=:  +/ . *
>>   C=: A - B=: (E=: (m,m) $ 1) mp A % m=: #A
>>   u=: ((mp~ |:) (-"1 mean)) % #
>>   v=: (mp~ |:)@(-"1 mean) % #
>>   u A
>> 504 360 180
>> 360 360   0
>> 180   0 720
>>   (|:C) mp A
>> 2520 1800  900
>> 1800 1800    0
>> 900    0 3600
>>
>> If I understand your presentation, those two results should have been
>> the same. But they are not...
>>
>> Can you run through your work with some example values and see whether
>> you think it's the presentation or my understanding of it that needs
>> to change?
>>
>> Thanks,
>>
>> --
>> Raul
>>
>>
>>
>>> On Mon, Feb 13, 2017 at 6:36 AM, Louis de Forcrand <[email protected]> wrote:
>>> A few corrections:
>>>
>>> u is
>>> (|:C) mp A % m
>>> and v is
>>> (|:C) mp C % m
>>> but we can multiply both by m when showing that they are equal.
>>>
>>> In addition, I forgot a division by m here:
>>>> +/ (i{Et) * j {"1 E
>>> that should read
>>> +/ (i{Et) * j {"1 E % m.
>>>
>>> Louis
>>>
>>>> On 13 Feb 2017, at 01:35, Louis de Forcrand <[email protected]> wrote:
>>>>
>>>> The two statements are executing two different procedures which happen to 
>>>> be mathematically equivalent:
>>>>
>>>> u=: ((mp~ |:) (-"1 mean)) % #
>>>> v=: (mp~ |:)@(-"1 mean) % #
>>>>
>>>> If (u -: v) A for a matrix A, then
>>>> (((mp~ |:) (-"1 mean)) -: (mp~ |:)@(-"1 mean)) A.
>>>>
>>>> Let
>>>> C=: A - B=: (E=: (m,m) $ 1) mp A % m=: #A
>>>> then u is
>>>> (|:C) mp A
>>>> and v is
>>>> (|:C) mp C.
>>>>
>>>> Let's look at u:
>>>> (|:C) mp A
>>>> (|:A-B) mp A
>>>> ((At=: |:A) - Bt=: |:B) mp A
>>>> (At mp A) - Bt mp A
>>>>
>>>> Now for v:
>>>> (|:C) mp C
>>>> (At - Bt) mp A - B
>>>> (At mp A) - (At mp B) - (Bt mp A) + Bt mp B
>>>>
>>>> We can see that if
>>>> (Bt mp B) -: At mp B
>>>> then (u -: v) A.
>>>>
>>>> At mp B
>>>> At mp E mp A % m
>>>>
>>>> Bt mp B
>>>> (|: E mp A % m) mp E mp A % m
>>>> At mp (Et=: |:E) mp E mp A % *:m
>>>> At mp (E mp E % m) mp A % m
>>>>
>>>> Now (and for the coup de grace):
>>>> (<i,j) { E mp E % m
>>>> +/ (i{Et) * j {"1 E
>>>> +/ (m$1) * m $ 1 % m
>>>> 1 for all i and j between 0 and m.
>>>> Therefor
>>>> E -: E mp E % m.
>>>>
>>>> And thus
>>>> Bt mp B
>>>> At mp E mp A % m
>>>> At mp B
>>>>
>>>> (u -: v) A for all matrices A. #
>>>>
>>>> Cheers,
>>>> Louis
>>>>
>>>> PS: I hope I didn't make and mistakes, but I might have. Thanks for 
>>>> checking!
>>>>
>>>>> On 12 Feb 2017, at 18:54, Raul Miller <[email protected]> wrote:
>>>>>
>>>>> It's not so much that it's of no use, but that it's redundant.
>>>>>
>>>>> When your hook is a train where the first verb is a hook, you can
>>>>> restructure either of them so that the other of those two hooks takes
>>>>> over the responsibility of obtaining the hook's "left argument"
>>>>> (presumably, this would eliminate the other hook).
>>>>>
>>>>> I hope this helps,
>>>>>
>>>>> --
>>>>> Raul
>>>>>
>>>>>
>>>>>> On Sun, Feb 12, 2017 at 10:18 AM, R.E. Boss <[email protected]> wrote:
>>>>>> I think the problem is that the big hook is of no use, that's what 
>>>>>> creates confusion.
>>>>>>
>>>>>> (data mp1 mn data)% # data
>>>>>> 504 360 180
>>>>>> 360 360   0
>>>>>> 180   0 720
>>>>>>
>>>>>> data mp1 mn data
>>>>>> 2520 1800  900
>>>>>> 1800 1800    0
>>>>>> 900    0 3600
>>>>>>
>>>>>> mp1 mn data
>>>>>> 2520 1800  900
>>>>>> 1800 1800    0
>>>>>> 900    0 3600
>>>>>>
>>>>>>
>>>>>> R.E. Boss
>>>>>>
>>>>>>
>>>>>> -----Original Message-----
>>>>>> From: Programming [mailto:[email protected]] On 
>>>>>> Behalf Of 'Mike Day' via Programming
>>>>>> Sent: zondag 12 februari 2017 12:02
>>>>>> To: [email protected]
>>>>>> Subject: Re: [Jprogramming] Hooked again
>>>>>>
>>>>>> It looks to me as if the two left hooks form one big left hook, not that 
>>>>>> I'm into boxing:
>>>>>>
>>>>>>  mn =: -"1 mean
>>>>>>  mp1=: mp~|:
>>>>>>
>>>>>>  ((mp1 mn)%#)data    NB. big "hook"
>>>>>> 504 360 180
>>>>>> 360 360   0
>>>>>> 180   0 720
>>>>>>
>>>>>>  ((mp1 @: mn)%#)data   NB. mp1 after mn using @:
>>>>>> 504 360 180
>>>>>> 360 360   0
>>>>>> 180   0 720
>>>>>>
>>>>>>  (([: mp1 mn)%#)data    NB. mp1 after mn using [:
>>>>>> 504 360 180
>>>>>> 360 360   0
>>>>>> 180   0 720
>>>>>>
>>>>>> Any use?
>>>>>>
>>>>>> Mike
>>>>>>
>>>>>>
>>>>>>> On 12/02/2017 08:06, Lippu Esa wrote:
>>>>>>> ]data=. 5 3 $ 90 60 90 90 90 30 60 60 60 60 60 90 30 30 30
>>>>>>>
>>>>>>> mean=: +/%#
>>>>>>> mp=:  +/ . *
>>>>>>> covmat=: ((mp~|:)(-"1 mean))%# NB. divede by n not n-1 to comply with
>>>>>>> the example
>>>>>>
>>>>>>
>>>>>> ---
>>>>>> This email has been checked for viruses by Avast antivirus software.
>>>>>> https://www.avast.com/antivirus
>>>>>>
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