Oh, I see what you are saying.

I somehow sidetracked onto a different issue.

My apologies.

Thanks,

-- 
Raul


On Mon, Feb 13, 2017 at 11:39 AM, Louis de Forcrand <[email protected]> wrote:
> I'm afraid that what is happenning here is not simple.
>
> u=: (mp~ |:) (-"1 mean)
> v=: (mp~ |:)@(-"1 mean)
>
> u A
> A mp~ |: (-"1 mean) A
> (|: A -"1 mean A) mp A
>
> v A
> (mp~ |:) A -"1 mean A
> (|: A -"1 mean A) mp A -"1 mean A
>
> It is not obvious that these two verbs are mathematically equivalent. That is 
> why my post may be hard to follow.
>
> Louis
>
>> On 13 Feb 2017, at 17:25, Raul Miller <[email protected]> wrote:
>>
>> Eh... ok, but that's pretty hard to follow, and there's much simpler
>> ways of recognizing what's going on here.
>>
>> --
>> Raul
>>
>>
>>> On Mon, Feb 13, 2017 at 10:15 AM, Louis de Forcrand <[email protected]> 
>>> wrote:
>>> I forgot to divide by m, see my correction.
>>>
>>> Louis
>>>
>>>> On 13 Feb 2017, at 15:24, Raul Miller <[email protected]> wrote:
>>>>
>>>> I'm having problems following your reasoning here.
>>>>
>>>> Consider:
>>>>
>>>>  A=: 5 3 $ 90 60 90 90 90 30 60 60 60 60 60 90 30 30 30
>>>>  mean=: +/%#
>>>>  mp=:  +/ . *
>>>>  C=: A - B=: (E=: (m,m) $ 1) mp A % m=: #A
>>>>  u=: ((mp~ |:) (-"1 mean)) % #
>>>>  v=: (mp~ |:)@(-"1 mean) % #
>>>>  u A
>>>> 504 360 180
>>>> 360 360   0
>>>> 180   0 720
>>>>  (|:C) mp A
>>>> 2520 1800  900
>>>> 1800 1800    0
>>>> 900    0 3600
>>>>
>>>> If I understand your presentation, those two results should have been
>>>> the same. But they are not...
>>>>
>>>> Can you run through your work with some example values and see whether
>>>> you think it's the presentation or my understanding of it that needs
>>>> to change?
>>>>
>>>> Thanks,
>>>>
>>>> --
>>>> Raul
>>>>
>>>>
>>>>
>>>>> On Mon, Feb 13, 2017 at 6:36 AM, Louis de Forcrand <[email protected]> 
>>>>> wrote:
>>>>> A few corrections:
>>>>>
>>>>> u is
>>>>> (|:C) mp A % m
>>>>> and v is
>>>>> (|:C) mp C % m
>>>>> but we can multiply both by m when showing that they are equal.
>>>>>
>>>>> In addition, I forgot a division by m here:
>>>>>> +/ (i{Et) * j {"1 E
>>>>> that should read
>>>>> +/ (i{Et) * j {"1 E % m.
>>>>>
>>>>> Louis
>>>>>
>>>>>> On 13 Feb 2017, at 01:35, Louis de Forcrand <[email protected]> wrote:
>>>>>>
>>>>>> The two statements are executing two different procedures which happen 
>>>>>> to be mathematically equivalent:
>>>>>>
>>>>>> u=: ((mp~ |:) (-"1 mean)) % #
>>>>>> v=: (mp~ |:)@(-"1 mean) % #
>>>>>>
>>>>>> If (u -: v) A for a matrix A, then
>>>>>> (((mp~ |:) (-"1 mean)) -: (mp~ |:)@(-"1 mean)) A.
>>>>>>
>>>>>> Let
>>>>>> C=: A - B=: (E=: (m,m) $ 1) mp A % m=: #A
>>>>>> then u is
>>>>>> (|:C) mp A
>>>>>> and v is
>>>>>> (|:C) mp C.
>>>>>>
>>>>>> Let's look at u:
>>>>>> (|:C) mp A
>>>>>> (|:A-B) mp A
>>>>>> ((At=: |:A) - Bt=: |:B) mp A
>>>>>> (At mp A) - Bt mp A
>>>>>>
>>>>>> Now for v:
>>>>>> (|:C) mp C
>>>>>> (At - Bt) mp A - B
>>>>>> (At mp A) - (At mp B) - (Bt mp A) + Bt mp B
>>>>>>
>>>>>> We can see that if
>>>>>> (Bt mp B) -: At mp B
>>>>>> then (u -: v) A.
>>>>>>
>>>>>> At mp B
>>>>>> At mp E mp A % m
>>>>>>
>>>>>> Bt mp B
>>>>>> (|: E mp A % m) mp E mp A % m
>>>>>> At mp (Et=: |:E) mp E mp A % *:m
>>>>>> At mp (E mp E % m) mp A % m
>>>>>>
>>>>>> Now (and for the coup de grace):
>>>>>> (<i,j) { E mp E % m
>>>>>> +/ (i{Et) * j {"1 E
>>>>>> +/ (m$1) * m $ 1 % m
>>>>>> 1 for all i and j between 0 and m.
>>>>>> Therefor
>>>>>> E -: E mp E % m.
>>>>>>
>>>>>> And thus
>>>>>> Bt mp B
>>>>>> At mp E mp A % m
>>>>>> At mp B
>>>>>>
>>>>>> (u -: v) A for all matrices A. #
>>>>>>
>>>>>> Cheers,
>>>>>> Louis
>>>>>>
>>>>>> PS: I hope I didn't make and mistakes, but I might have. Thanks for 
>>>>>> checking!
>>>>>>
>>>>>>> On 12 Feb 2017, at 18:54, Raul Miller <[email protected]> wrote:
>>>>>>>
>>>>>>> It's not so much that it's of no use, but that it's redundant.
>>>>>>>
>>>>>>> When your hook is a train where the first verb is a hook, you can
>>>>>>> restructure either of them so that the other of those two hooks takes
>>>>>>> over the responsibility of obtaining the hook's "left argument"
>>>>>>> (presumably, this would eliminate the other hook).
>>>>>>>
>>>>>>> I hope this helps,
>>>>>>>
>>>>>>> --
>>>>>>> Raul
>>>>>>>
>>>>>>>
>>>>>>>> On Sun, Feb 12, 2017 at 10:18 AM, R.E. Boss <[email protected]> 
>>>>>>>> wrote:
>>>>>>>> I think the problem is that the big hook is of no use, that's what 
>>>>>>>> creates confusion.
>>>>>>>>
>>>>>>>> (data mp1 mn data)% # data
>>>>>>>> 504 360 180
>>>>>>>> 360 360   0
>>>>>>>> 180   0 720
>>>>>>>>
>>>>>>>> data mp1 mn data
>>>>>>>> 2520 1800  900
>>>>>>>> 1800 1800    0
>>>>>>>> 900    0 3600
>>>>>>>>
>>>>>>>> mp1 mn data
>>>>>>>> 2520 1800  900
>>>>>>>> 1800 1800    0
>>>>>>>> 900    0 3600
>>>>>>>>
>>>>>>>>
>>>>>>>> R.E. Boss
>>>>>>>>
>>>>>>>>
>>>>>>>> -----Original Message-----
>>>>>>>> From: Programming [mailto:[email protected]] On 
>>>>>>>> Behalf Of 'Mike Day' via Programming
>>>>>>>> Sent: zondag 12 februari 2017 12:02
>>>>>>>> To: [email protected]
>>>>>>>> Subject: Re: [Jprogramming] Hooked again
>>>>>>>>
>>>>>>>> It looks to me as if the two left hooks form one big left hook, not 
>>>>>>>> that I'm into boxing:
>>>>>>>>
>>>>>>>> mn =: -"1 mean
>>>>>>>> mp1=: mp~|:
>>>>>>>>
>>>>>>>> ((mp1 mn)%#)data    NB. big "hook"
>>>>>>>> 504 360 180
>>>>>>>> 360 360   0
>>>>>>>> 180   0 720
>>>>>>>>
>>>>>>>> ((mp1 @: mn)%#)data   NB. mp1 after mn using @:
>>>>>>>> 504 360 180
>>>>>>>> 360 360   0
>>>>>>>> 180   0 720
>>>>>>>>
>>>>>>>> (([: mp1 mn)%#)data    NB. mp1 after mn using [:
>>>>>>>> 504 360 180
>>>>>>>> 360 360   0
>>>>>>>> 180   0 720
>>>>>>>>
>>>>>>>> Any use?
>>>>>>>>
>>>>>>>> Mike
>>>>>>>>
>>>>>>>>
>>>>>>>>> On 12/02/2017 08:06, Lippu Esa wrote:
>>>>>>>>> ]data=. 5 3 $ 90 60 90 90 90 30 60 60 60 60 60 90 30 30 30
>>>>>>>>>
>>>>>>>>> mean=: +/%#
>>>>>>>>> mp=:  +/ . *
>>>>>>>>> covmat=: ((mp~|:)(-"1 mean))%# NB. divede by n not n-1 to comply with
>>>>>>>>> the example
>>>>>>>>
>>>>>>>>
>>>>>>>> ---
>>>>>>>> This email has been checked for viruses by Avast antivirus software.
>>>>>>>> https://www.avast.com/antivirus
>>>>>>>>
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