Thanks.
I found that after I couldn't find it and wrote my own, but it seemed to be
changing one of my function parameters, the left one, so I moved back to my
definition.
I'm again having a similar problem stringing these verbs, adverbs, etc.
together to form the function I want.
I created an 15 by 15 identity matrix, call it id, and substituted this
(1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |.!.0~
3 1 $ -)
for this
(id {~)
Much cleaner and, no doubt, faster. Win. Win.
Naively, I thought this simple substitution of the two would work
make_move =: ((+. *. -.@:*.) +./) (id {~)
Nope. Syntax error.
Have already tried several other variations this AM with the same result.
I'm using "Learning J" as a reference and NuVoc.
http://www.jsoftware.com/help/learning/contents.htm
On Sun, May 28, 2017 at 9:57 PM, David Lambert <[email protected]> wrote:
> xor can be not equal ~:
>
> or bitwise 2b10110 b.
>
>
>
> On 05/28/2017 08:00 AM, [email protected] wrote:
>
>> Message: 5
>> Date: Sat, 27 May 2017 23:51:29 -0400
>> From: Michael Rice<[email protected]>
>> To: programming<[email protected]>
>> Subject: Re: [Jprogramming] Function creation, without creating
>> subfunctions
>> Message-ID:
>> <CAGw08vM_5CttMFY45F6zAAto-doycQYkXqRf8uRWC=0Ug9xcOw@mail.
>> gmail.com>
>> Content-Type: text/plain; charset="UTF-8"
>>
>> Yes, that worked. New board created, without changing the old board or the
>> move.
>>
>> board =: 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1
>> move =: 0 2 5
>> make_move =: ((+. *. -.@:*.) +./) (1 0 0 0 0 0 0 0 0 0 0 0 0 0 0
>> |.!.0~
>> 3 1 $ -)
>> board make_move move
>> 0 1 0 1 1 1 1 1 1 1 1 1 1 1 1
>> board
>> 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1
>> move
>> 0 2 5
>>
>
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