Yes I guess it could be replaced by
u”_1”_1 _
I would guess it is the intended behavior as b.0 reports
infinite rank, but that is what I find strange.
Louis
> On 07 Aug 2017, at 16:47, Xiao-Yong Jin <jinxiaoy...@gmail.com> wrote:
>
> I remembered I had problem with this and ended up specifying both left and
> right rank.
>
> JVERSION
> Engine: j806/j64avx/darwin
> Beta-4: commercial/2017-06-27T12:55:06
> Library: 8.06.03
> Platform: Darwin 64
> Installer: J806 install
> InstallPath: /applications/j64-806
> Contact: www.jsoftware.com
> +"_1 _ b.0
> _ _ _
> +"_1 _/~i.3
> 0 1 2
> 1 2 3
> 2 3 4
>
> I'm not sure if it is the intended behavior.
>
>
>> On Aug 7, 2017, at 3:40 PM, Louis de Forcrand <ol...@bluewin.ch> wrote:
>>
>> +"0/~ i.3
>> 0 1 2
>> 1 2 3
>> 2 3 4
>> +"_1/~ i.3
>> 0 2 4
>> +"0 b.0
>> 0 0 0
>> +"_1 b.0
>> _ _ _
>>
>> I understand that this is dictionary compliant:
>>
>> "In general, each cell of x is applied to the entire of y . Thus x u/ y is
>> equivalent to x u"(lu,_) y where lu is the left rank of u ."
>>
>> +"_1 b.0
>> _ _ _
>>
>> So u"_1/ -: u"_ _ . Wouldn’t it be better though if u"_1/ -: u"_1 _ ,
>> or if (u”_1 b.0) -: _1 _1 _1 (or any other negative rank)?
>> I ran into this while trying to use ,"_1/ , which I can replace by >@{@,&< ,
>> but I still find this strange.
>>
>> Louis
>>
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