Hi all !
Case 1:
3!:0 [ (n^2)
8
(n^2) | 5729082486784839
0
It is non-intuitive that an integer raised to an integer is a float, but
I think it is normal. It would be possible with a performance penalty to
get an integer result. One problem with that is that it would easily
overflow. It would also be possible to have a special operation for this
case.
When the left argument is a float the right argument has to be converted
to a float. It must be assumed that this conversion is intentional, even
though it is implicit.
Case 2:
3!:0 [ (n^2)
8
(n^2) | 5729082486784839x
0
3!:0 (n^2) | 5729082486784839x
8
Here the rational seems to be converted to a float and the result is
float. Shouldn't we have an error instead of converting rationals to float?
Case 3:
3!:0 (x: n^2)
128
(x: n^2) | 5729082486784839
0
3!:0 (x: n^2) | 5729082486784839
128
I have a hard time understanding what happens here. This result seems
very peculiar. Is the left and right argument converted to float and the
float result converted to rational?!
Shouldn't we have an error instead of converting rationals to float?
We could not have floats auto-converted to rationals?
In this case the integer should be converted to rational and we should
get a rational result?
It is non-intuitive that (*: n) does not give the same result as (n^2).
Maybe once this was decided because of performance reasons.
Cheers,
Erling Hellenäs
On 2017-09-05 18:41, Rob B wrote:
Could someone explain this please?
n=.14
n
14
(*: n) | 5729082486784839
147
196 | 5729082486784839
147
(n^2) | 5729082486784839
0
(n^2) | 5729082486784839x
0
(x: n^2) | 5729082486784839
0
(x: n^2) | 5729082486784839x
147
Regards, Rob Burns
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