You did not give an example of what you want to see, and your description allows for at least two different interpretations:
f1=: 4 :'x`:6 y'"_1 f2=: 4 :'((#y)$x) f1 y' They both give the same result when x and y have the same number of items. What are you trying to do? Thanks, -- Raul On Sun, Sep 24, 2017 at 6:43 AM, Rob Moore <robmoore...@gmail.com> wrote: > Hi guys, > > I am wondering if there already exists a way of doing something that I > want, which is an elementary enough operation that I was quite surprised to > not have found it in jvoc/evoke gerund. > > > If I have some gerund say *:`+: I am looking for some function which will > apply the gerund's constituents in order (from right to left of course) > monadically to some noun. > > > For example '(*:`+:) f 4' should be equivalent to '*: +: 4' (which is 64) > > > My current solution is functional but unsatisfactory. Convert gerund to > string, append the (string) argument and then apply 'do' ". > > > composeGerund=:".@:((,@:(,"1&' ')@:>@:[) , ]) > > > e.g: > > > gerund=:*:`+: > > , ,"1&' ' >gerund > > *: +: > > (, ,"1&' ' >gerund) , '4' > > *: +: 4 > > ". (, ,"1&' ' >gerund) , '4' > > 64 > > > I don't want to have to specify my right argument as a string, I want to > pass in variables by value! > > > Does anyone have a good solution? > > > Cheers, > > > Rob > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
