Ah, sorry, I had not read your original post close enough. That's a
bad habit, and I need to do better on reading other people's concepts.
That said, I can offer some variants on Jose's approach:
at=:4 :0
x`:6@:(y`:6)`''
)
Example use:
at/(]`{.`{:`{:)
Or, equivalently:
at=: (<'@:') ,@<@, <@,
Thanks,
--
Raul
On Sun, Sep 24, 2017 at 2:35 PM, Rob Moore <[email protected]> wrote:
> Thanks for replying Raul, your solutions weren't what I was looking for,
> but I understand the confusion from my first explanation.
>
> Jose your first solution worked perfectly, thanks very much! The other two
> solutions you gave caused syntax errors for me, must be different versions,
> I'm on 604.
>
> What did you mean by compliant and non-compliant in your comments?
>
> Thanks,
>
> Rob
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