On 27 September 2017 at 19:13, 'Mike Day' via Programming
<[email protected]> wrote:
> ($$rplc & (' 0';' ')) @: ": a
Yes. (I guess the @: is unnecessary here, right?)
I actually had tried something similar first:
(' 0';' ') stringreplace ":r
which, however, yielded
1 2 3 4 5 6 7 8 9 10 11 12 13 14 1516 17 18 19 20 21 2223 24 25 26 27 28 2930 31
I didn't (and still don't) understand why I got a single line, and
decided to ask for help then...
I see (if I understand) you put the shape back in with $$...
so in my case it would be
($$ (' 0';' ')& stringreplace) ":r
Thanks
Ruda
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