On 28 September 2017 at 14:50, Raul Miller <[email protected]> wrote:
> Another way to work around this problem would be to use stringreplace"1
>
> r=: _7 ]\ 0 >. i.&.(+&5) 32
> (":r) rplc"1 ' 0';' '
Ok. Thanks. So is there a good reason for txt=. ,y in stringreplace?
Or, can the whole of r be represented as just a (single) list of characters,
like
a =. 0 : 0
1 0 3
0 4 5
)
a
1 0 3
0 4 5
$a
14
a rplc ' 0';' '
1 3
4 5
i.e., here the rplc can be used directly...
Thanks
Ruda
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