Hi all! Raul:
"Hmm... actually, thinking about it, the par approach here is not efficient enough for this example. 5 parRuskeyE 32 is too big of a result, I think. (358358 has 5 distinct prime factors and, thus, 32 integer factors.)" However there are only 5 integer factors: q: 358358 2 7 11 13 179 */q:358358 358358 Now you ask me for 44 5 integer factorizations. As far as I understand there is only one 5 integer factorization of 358358 unless you count 1 and 358358 as factors. In any case it can be handled by parRuskeyE. Cheers, Erling Hellenäs
Den 2017-11-03 kl. 10:58, skrev Raul Miller:
I'm not sure where you showed the 44 different 5 integer factorizations of 358358? Thanks,
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