OK. The five prime factors are needed if you want to multiply 5 numbers and get 358358, except that you can possibly add zeros and  358358 itself? /Erling

On 2017-11-03 14:35, 'Mike Day' via Programming wrote:
Language differences?

Personally,  I tend to be rather careless,  using the terms “factor” and 
“divisor” for the same thing,  when “divisor” is perhaps to be preferred.  
However,  Pari GP provides a library function “factor” to deliver the prime 
factorisation of its argument,  in a similar fashion to J’s q: .

So, strictly speaking,  perhaps,  the factors of 358358 are 2 7 11 13 179 and 
its divisors are 1 2 7 11 13 14 22 etc...

You’re both right!

Mike

Please reply to [email protected].
Sent from my iPad

On 3 Nov 2017, at 11:25, Erling Hellenäs <[email protected]> wrote:

Hi all!

Raul:

"Hmm... actually, thinking about it, the par approach here is not
efficient enough for this example. 5 parRuskeyE 32 is too big of a
result, I think. (358358 has 5 distinct prime factors and, thus, 32
integer factors.)"

However there are only 5 integer factors:

   q: 358358
2 7 11 13 179
   */q:358358
358358

Now you ask me for 44 5 integer factorizations.

As far as I understand there is only one 5 integer factorization of 358358 
unless you count 1 and 358358 as factors.
In any case it can be handled by parRuskeyE.

Cheers,

Erling Hellenäs



Den 2017-11-03 kl. 10:58, skrev Raul Miller:
I'm not sure where you showed the 44 different 5 integer
factorizations of 358358?

Thanks,

----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm


----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm

Reply via email to