We have a problem in the Rank operator, which I described. I am trying
to create a discussion about solutions to this problem. /Erling
Den 2017-12-20 kl. 13:31, skrev Raul Miller:
Actually, J does support arrays of nothing. That's what i.0 is, after
all. And, if you want a scalar containing an array of nothing, then a:
matches that specification.
And we have an algebra here - though if (as in your previous message)
you do multiplication and call it addition, this becomes very
difficult to talk about.
That said, remember that we can add an arbitrary number of leading 1
dimensions to any array without changing the number of elements in
that array.
Thanks,
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