(1) this is not a problem with the Rank operator (2) wrong forum - almost none of the messages here have any programming in them and almost none of this is about writing j programs.
Thanks, -- Raul On Wed, Dec 20, 2017 at 9:00 AM, Erling Hellenäs <[email protected]> wrote: > We have a problem in the Rank operator, which I described. I am trying to > create a discussion about solutions to this problem. /Erling > > > Den 2017-12-20 kl. 13:31, skrev Raul Miller: >> >> Actually, J does support arrays of nothing. That's what i.0 is, after >> all. And, if you want a scalar containing an array of nothing, then a: >> matches that specification. >> >> And we have an algebra here - though if (as in your previous message) >> you do multiplication and call it addition, this becomes very >> difficult to talk about. >> >> That said, remember that we can add an arbitrary number of leading 1 >> dimensions to any array without changing the number of elements in >> that array. >> >> Thanks, >> > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
