True, you would wind up having to incorporate @{. into each cell of
your gerund, when that mattered - if it worked at all.

But it currently gives a nonce error, which I think is a bigger problem.

Thanks,

-- 
Raul


On Sun, Jan 7, 2018 at 12:31 PM, Henry Rich <[email protected]> wrote:
> The problem with u;.3, or 1 u\, is that the verb acts on a subarray of y
> rather than on a cell of y, which gives the result higher rank than you
> want:
>
>   $L:0 (,.1 1) <;.3] i.4
> +-+-+-+-+
> |1|1|1|1|
> +-+-+-+-+
>
> Henry Rich
>
> On 1/7/2018 12:27 PM, Raul Miller wrote:
>>
>> It finally occurred to me, months after the "rank with cyclic gerund"
>> discussions, that J already has a cyclic gerund definition, in u;.3
>>
>> However, testing it, I get a nonce error for the gerund case:
>>
>>     (,.1 1) <;.3] i.4
>> ┌─┬─┬─┬─┐
>> │0│1│2│3│
>> └─┴─┴─┴─┘
>>     (,.1 1) +:`-:;.3] i.4
>> |nonce error
>>
>> We even have the obvious simplification for the non-gerund case:
>>
>>     1 <;.3] i.4
>> ┌─┬─┬─┬─┐
>> │0│1│2│3│
>> └─┴─┴─┴─┘
>>
>> I've not investigated the source code yet, behind that nonce error,
>> I'm just leaving this here to give me a chance of remembering it,
>> later.
>>
>> FYI,
>>
>
>
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