Yeah!
Henry Rich
On 1/17/2018 12:51 AM, Crypto Geek wrote:
+/_5{.\100+i.900
On Jan 16, 2018, at 11:39 PM, Skip Cave <[email protected]> wrote:
I want to find the sum of all the three-digit numbers that are divisible by
5 (Quora problem).
My explicit solution is:
+/a#~0=5|a=.100+i.900
98550
To find a tacit version:
sm=. +/a#~0=5|a=.100+i.900
sm
[: ([: +/ ] #~ 0 = 5 | ]) (100+i.900)"_
Is there a more compact way to express this function tacitly?
Skip
Skip Cave
Cave Consulting LLC
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
---
This email has been checked for viruses by AVG.
http://www.avg.com
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
