Very nice Crypto Geek,
I had looked for a bit at other ways to get the total, but I sure hadn't come
up with anything as pretty as that.
I suppose technically the tacit form would be +/@(_5{.\100+i.) since the 900 is
the argument
+/@(_5{.\100+i.)900
98550
Cheers, bob
> On Jan 16, 2018, at 9:51 PM, Crypto Geek <[email protected]> wrote:
>
> +/_5{.\100+i.900
>
>
>> On Jan 16, 2018, at 11:39 PM, Skip Cave <[email protected]> wrote:
>>
>> I want to find the sum of all the three-digit numbers that are divisible by
>> 5 (Quora problem).
>>
>> My explicit solution is:
>>
>> +/a#~0=5|a=.100+i.900
>> 98550
>>
>> To find a tacit version:
>>
>> sm=. +/a#~0=5|a=.100+i.900
>>
>> sm
>>
>> [: ([: +/ ] #~ 0 = 5 | ]) (100+i.900)"_
>>
>>
>> Is there a more compact way to express this function tacitly?
>>
>>
>> Skip
>>
>>
>> Skip Cave
>> Cave Consulting LLC
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