*:5 is 25 which has an integer square root, so %: *: 5 has a result which is exactly 5
%:5 does not have an integer result, but instead has a floating point (approximate) result, so *: %: 5 has a result which is approximately 5. -- Raul On Fri, Mar 23, 2018 at 2:04 PM, Martin Kreuzer <[email protected]> wrote: > Having read through > http://code.jsoftware.com/wiki/Essays/Tolerant_Comparison > (as far as I managed to follow the reasoning) > I tried these examples: > > 5 (=!.0) %: *: 5 > 1 > 5 (=!.0) *: %: 5 > 0 > > 5 - %: *: 5 > 0 > 5 - *: %: 5 > _8.88178e_16 > (*:&%: - %:&*:) 5 > 8.88178e_16 > > and have been wondering since how/why the order of evaluation would make a > difference (having expected it to throw a zero in *both* cases). > I'm aware of the the asymmetric interval boundaries x*1-t ; x%1-t but can't > figure out whether they might be involved in the differing of results, as > the tolerance is set to zero. > > Anybody volunteering with a layman's explanation..? > > -M > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
