Thanks, this makes sense. Actually it is even easier, hopefully. The verb is 
formed by `:6 a sequence of
gerunds. I can figure out which gerunds terminate which subsequences of the 
gerund train before  even
performing `:6.

e.g +:`[`^
only +: is evaluated.

Thanks,
Jon
--------------------------------------------
On Fri, 3/23/18, Henry Rich <[email protected]> wrote:

 Subject: Re: [Jprogramming] Recognizing unused parts of a tacit verb train
 To: [email protected]
 Date: Friday, March 23, 2018, 6:19 PM
 
 When dissect is constructing the
 display, gets to
 
 (f [ h)
 
 it knows that the execution of
 h is immaterial unless it encounters an 
 error.  It displays only the f part.
 
 It then grays out any part of
 the sentence that is not displayed.
 
 Notice that it also grays out the leading ] and
 the ] in the @:], which 
 are also not
 needed.
 
 There is an option
 to display both sides of ][.
 
 Using the transformations
 
 (f [ h) -> f
 (] g@]) ->
 (] g)
 (] g) -> g@]
 (f@] g
 h@])-> (f g h)@]
 
 you can
 turn it into
 
 (2&o. +
 1&o.)@]
 
 Henry Rich
 
 
 
 On 3/23/2018 3:26 AM, 'Jon Hough' via
 Programming wrote:
 > Consider the
 following tacit verb
 > f1=: ]
 (2&o.@:] + 1&o.@:] [ 5&+@:] 7&+@:] ([: <.
 ]) 10&*@:] 7&*@:])
 >
 > It looks strange, and is pretty long. The
 interesting point is that only the left
 >
 section  ] (2&o.@:] + 1&o.@:]   is useful. The
 rest of it is not evaluated.
 > i.e. f1 is
 equivalent to sin(x) + cos(x).
 >
 > I noticed that the dissect tool recognizes
 this fact.
 > dissect '(] (2&o.@:]
 + 1&o.@:] [ 5&+@:] 7&+@:] ([: <. ])
 10&*@:] 7&*@:])) 1'
 >
 > Everything but the sin(x) + cos(x) par tis
 greyed out, implying it is not evaluated.
 > My question is, how does dissect recognize
 this? And is it possible to extract a simplified
 > tacit verb from f1?
 >
 >
 >
 Thanks,
 > Jon
 >
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