This is more math, than eager/lazy evaluation issue.

Though if lazy (programmer), you might use solution for 10 and 100 to guess at 
1M.

It's an extention of unique pairs that add up to a sum. <.@-: sum

The extention is a matter of avoiding duplicates while summing to 1M less the 
largest of the triplets, for eacch "largest triplet"



________________________________
From: Henry Rich <henryhr...@gmail.com>
To: programm...@jsoftware.com 
Sent: Saturday, May 19, 2018 6:41 PM
Subject: Re: [Jprogramming] Quora Problem



I don't think it's the interpreter's strategy that is at fault. odo 
3#1e6 is asking the machine to create a set of 1e18 triplets, which you 
will then presumably check to see if they add to 1e6, and then cast out 
duplicates.  If somehow the interpreter could feed you the 1e18 values 
one at a time, you still wouldn't get to a solution.

A better strategy is to read about partitions and generating functions 
thereof.

Henry Rich

On 5/19/2018 5:58 PM, james faure wrote:
> This is a good example of a very annoying limitation of the current 
> interpreter's eager evaluation strategy, in this case one is forced to come 
> up with some sort of non-idiomatic iterative 'hack' to get a result. 
> Concretely, I guess you're forced to use an accumulator with ^: or an 
> explicit loop, which hurts.
>
> ________________________________
> From: Programming <programming-boun...@forums.jsoftware.com> on behalf of 
> Skip Cave <s...@caveconsulting.com>
> Sent: Saturday, May 19, 2018 10:43 PM
> To: programm...@jsoftware.com
> Subject: [Jprogramming] Quora Problem
>
> Another interesting quora problem:
>
> How many distinct triplets have a sum of 1,000,000 (provided all numbers
> are integers and are positive)?
> <https://www.quora.com/qemail/track_click?al_imp=eyJ0eXBlIjogMzUsICJoYXNoIjogMTcxMDQ0NjU4Mn0%3D&al_pri=QuestionLinkClickthrough&aoid=oMo937UDzj8&aoty=2&aty=4&click_pos=1&ct=1526747413834671&et=103&id=62216bf7b30d40aea1d79bf4401c8317&request_id=289&src=1&st=1526747413838426&stories=2518686273&uid=bqluVqSeN78&v=0>
>
> The obvious straightforward solution would be to use the odometer verb:
>
> odo=: #: i.@(*/)
>
> 1e6=+/"1 odo 3#1e6
>
> |limit error: odo
>
> | 1000000=+/"1 odo 3#1000000
>
>
> Ooops. Unfortunately, I don't have near enough memory to use this approach.
>
> Any suggestions?
>
>
> Skip
>
>
>
> Skip Cave
> Cave Consulting LLC
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