Also, in this example, ‘name’ was meant to represent a pronoun.
Thanks,
—
Raul
On Friday, August 24, 2018, Henry Rich <henryhr...@gmail.com> wrote:
> ".@'name' is a verb. In
>
> [x] ".@'name' y
>
> y (and x if given) are ignored, and the result is the value of (name) when
> the verb is executed.
>
> This is the same as it used to be, but is now faster.
>
> Henry Rich
>
> On 8/23/2018 10:22 PM, Brian Schott wrote:
>
>> Henry, I'm still a little lost.
>> Is the final `npixels` a (monadic, in this case) verb which will take a
>> noun argument,
>> or is the current value of windowsize that noun.
>>
>> If the latter, and windowsize is that noun, then what is the value of y in
>> the original expression `[x] ".@'name' y`?
>>
>> If the former (`npixels` is a verb -- and this is the one I'm leaning
>> toward), then what is the y value that is its argument?
>>
>> TIA.
>>
>> On Thu, Aug 23, 2018 at 9:41 PM, Henry Rich <henryhr...@gmail.com> wrote:
>>
>> Often you need for a verb to refer to the value of a name when the noun is
>>> executed, rather than when it is defined. So, rather than
>>>
>>> npixels =: */ windowsize
>>>
>>> which would just be a noun, you write
>>>
>>> npixels =: 3 : '*/ windowsize'
>>>
>>> to defer taking the value of (windowsize) until (npixels) is executed.
>>>
>>> In tacit code, you used to write
>>>
>>> npixels =: */ @: ". @ ('windowsize'"_)
>>>
>>> to get the same result. Recently the syntax was added to allow
>>>
>>> npixels =: */ @: ". @ 'windowsize'
>>>
>>> All that still works. But the (".) verb starts the parser and executes
>>> its y argument as a sentence, with a modest overhead that will matter if
>>> the verbs have small ranks. Now, you can write
>>>
>>> npixels =: */ @: (". @ 'windowsize')
>>>
>>> [parentheses important! make sure you see why]. When (npixels) is
>>> defined, this form will detect that the argument to (".) is a single
>>> name.
>>> When (npixels) is executed, the name will be evaluated without going
>>> through the overhead of starting a sentence.
>>>
>>> Henry Rich
>>>
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