I'd call it random shape rather than random rank. The rank is fixed at 3.
The sequence of steps I'm finding is
DATA =: 'ABCDEFFGHIJKLMNOPSSTUVXYZ'
SHAPE =: >: ? 3 # 5 NB. zeros aren't beneficial to this demonstration
A =: SHAPE $ DATA NB. A is a rank 3 array of random shape
ITEM_RANK =: ? >: rank A
(;:'array items') , ( (< A) ; ( < <"ITEM_RANK A) ) , ( SHAPE ; ITEM_RANK )
Please remove this comment. AD isn't defined, the comment doesn't alter
D but looks like it does.
NB.verb ra m]D=:3 4 5$AD
C isn't used again. I wouldn't define it.
It looks as if D is intended to choose items of rank zero through the
rank of B (which is 3).
Hence
D =: ? >: # $ B NB. (or just ? 4 )
E =: <"D B
And then explain the table
"box all of B" "Box rank D items of B"
Thanks!
Dave
On 09/23/2018 08:00 AM, [email protected] wrote:
Date: Sun, 23 Sep 2018 01:34:25 +0000
From: Linda Alvord<[email protected]>
To:"[email protected]" <[email protected]>
Subject: Re: [Jprogramming] Using rank to avoid looping - reference?
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<bn6pr06mb3137f32fdcdaaaeb4a90313db5...@bn6pr06mb3137.namprd06.prod.outlook.com>
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I made a little series of steps to illustrate the difeence between the two
ranks. Did I get rthe differences right?
NB. Random rank noun B
NB. and random rank verb b ox
A=:'ABCDEFFGHIJKLMNOPSSTUVXYZ'
]C=:<B=:(>:?3#5)$A
┌─┐
│A│
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