Yes. And it does the same for the dyadic case.
I wonder why this was done; and whether this or anything else should be
done in this case.
Henry Rich
On 11/17/2018 12:05 PM, 'Pascal Jasmin' via Programming wrote:
-:`+^:_1 i.5
0 0.5 1 1.5 2
it applies the first verb. ignoring 2nd, and if there are more length error.
Hard to see usefulness, and if there was some, v0`v1`...vn^:n should behave
like v0^:n
Though, I'm fine with error.
________________________________
From: Henry Rich <[email protected]>
To: [email protected]
Sent: Saturday, November 17, 2018 11:54 AM
Subject: Re: [Jprogramming] What does gerund^:n do?
+`*`- i.5
is simply an execution of dyad i., looking up 5 in the boxed list.
+`*:^:_1 i.5
0 1 2 3 4
seems to result in y
gerund not length 2 is a length error?
other n seem to be domain errors including 0
Now you're getting warm. The first statement is false, the other two
are true.
Henry Rich
On 11/17/2018 11:04 AM, 'Pascal Jasmin' via Programming wrote:
first there is
+`- i.5
2
+`*`- i.5
3
seems like the number of items in gerund is the result no matter what?
+`*:^:_1 i.5
0 1 2 3 4
seems to result in y
gerund not length 2 is a length error?
other n seem to be domain errors including 0
I'm ok with making this an error, rather than "improving" functionality to do something
"powerful"
________________________________
From: Henry Rich <[email protected]>
To: [email protected]
Sent: Saturday, November 17, 2018 10:39 AM
Subject: Re: [Jprogramming] What does gerund^:n do?
No. All I see are domain errors when you try gerund^:n . The question
is, For what values of gerund and n does gerund^:n not fail, and what
does it do then?
(I already know the answer because I'm looking at the source code,
wondering whether this is functionality we ought to keep)
Henry Rich
On 11/17/2018 10:35 AM, Brian Schott wrote:
Does this shed any light?
gerund =. +`-
gerund/ i. 10
9
gerund/ i. 11
_1
gerund^: i. 11
|domain error
| gerund ^:i.11
gerund^:3 i. 11
|domain error
| gerund ^:3 i.11
gerund^:3] i. 11
|domain error
| gerund ^:3]i.11
vgerund =. -
vgerund^:3] i. 11
0 _1 _2 _3 _4 _5 _6 _7 _8 _9 _10
On Sat, Nov 17, 2018 at 10:20 AM Henry Rich <[email protected]> wrote:
(Actually, I know the answer to this, but I can't find it in the
documents anywhere & I wonder why it's supported).
For certain gerunds and certain n,
gerund^:n
does not produce an error. What does it do?
Henry Rich
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