It seems to be just academic now.  Nevertheless, does your interpretation
imply that,

   5"
5"

is not "reduced" but,

   5}
5}

is "reduced" in the context of shift-reduce parsers?


On Mon, Dec 10, 2018 at 10:43 AM Raul Miller <[email protected]> wrote:

> On Fri, Dec 7, 2018 at 7:53 PM Henry Rich <[email protected]> wrote:
> > What Ken meant by "resolve" is not clear to me.
>
> I expect he meant what people working with shift-reduce parsers would
> call "reduce". (But Ken would not be inclined to call it that, I
> imagine, because reduce was a similar/different well defined APL
> operation.)
>
> Thanks,
>
> --
> Raul
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