Obviously the squares >2018 don't play any role whatsoever, so you can restrict yourself to %:2018
>a#~2018=>+/ each a=.;<@(<\.)\2^~i.>.%:2018 49 64 81 100 121 144 169 196 225 256 289 324 R.E. Boss > -----Oorspronkelijk bericht----- > Van: Programming <programming-boun...@forums.jsoftware.com> > Namens Skip Cave > Verzonden: donderdag 24 oktober 2019 19:12 > Aan: programm...@jsoftware.com > Onderwerp: Re: [Jprogramming] Quora problem > > To me it seems that R. E. Boss provided the simplest approach. > Don't know about efficiency, but the results appear instantly: > > >a#~2018=>+/ each a=.;<@(<\.)\2^~i.100 > > 49 64 81 100 121 144 169 196 225 256 289 324 > > Skip > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
