See also https://www.wikiwand.com/en/Stigler%27s_law_of_eponymy


R.E Boss


> -----Oorspronkelijk bericht-----
> Van: Programming <programming-boun...@forums.jsoftware.com>
> Namens R.E. Boss
> Verzonden: vrijdag 25 oktober 2019 13:31
> Aan: programm...@jsoftware.com
> Onderwerp: Re: [Jprogramming] Quora problem
> 
> Good ideas have many parents.
> 
> 
> R.E. Boss
> 
> 
> > -----Oorspronkelijk bericht-----
> > Van: Programming <programming-boun...@forums.jsoftware.com>
> > Namens Roger Hui
> > Verzonden: donderdag 24 oktober 2019 21:30
> > Aan: programm...@jsoftware.com
> > Onderwerp: Re: [Jprogramming] Quora problem
> >
> > The "all prefixes of suffixes" (or "all suffixes of prefixes") idea
> > was posted by Marshall Lochbaum in September 2011.
> >
> > http://www.jsoftware.com/pipermail/programming/2011-
> > September/023954.html
> >
> > On Thu, Oct 24, 2019 at 11:30 AM Skip Cave <s...@caveconsulting.com>
> > wrote:
> >
> > > I find R. E. Boss' function quite useful in many instances. I call
> > > it "all sets". Is this a standard idiom in J? Is there a more
> > > efficient construction that does this? Is there a primitive that does 
> > > this?
> > >
> > > as=.3 :';<@(<\.)\y' NB. All Sets
> > >
> > > as i.5
> > >
> > > │0│0 1│1│0 1 2│1 2│2│0 1 2 3│1 2 3│2 3│3│0 1 2 3 4│1 2 3 4│2 3 4│3
> > > 4│4│
> > >
> > >
> > > Skip
> > >
> > >
> > >
> > > On Thu, Oct 24, 2019 at 12:30 PM R.E. Boss <r.e.b...@outlook.com>
> wrote:
> > >
> > > > Obviously the squares >2018 don't play any role whatsoever, so you
> > > > can restrict yourself to %:2018
> > > >
> > > >    >a#~2018=>+/ each a=.;<@(<\.)\2^~i.>.%:2018
> > > > 49 64 81 100 121 144 169 196 225 256 289 324
> > > >
> > > > R.E. Boss
> > > >
> > > >
> > > > > -----Oorspronkelijk bericht-----
> > > > > Van: Programming <programming-boun...@forums.jsoftware.com>
> > > > > Namens Skip Cave
> > > > > Verzonden: donderdag 24 oktober 2019 19:12
> > > > > Aan: programm...@jsoftware.com
> > > > > Onderwerp: Re: [Jprogramming] Quora problem
> > > > >
> > > > > To me it seems that R. E. Boss provided the simplest approach.
> > > > > Don't know about efficiency, but the results appear instantly:
> > > > >
> > > > > >a#~2018=>+/ each a=.;<@(<\.)\2^~i.100
> > > > >
> > > > > 49 64 81 100 121 144 169 196 225 256 289 324
> > > > >
> > > > > Skip
> > > > > ----------------------------------------------------------------
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