solve: (x^x)=2*x
JVERSION
Engine: j901/j64avx2/windows
Release-e: commercial/2020-01-29T11:17:19
Library: 9.01.18
Qt IDE: 1.8.5/5.12.6
Platform: Win 64
Installer: J901 install
InstallPath: c:/users/skip/j901
Contact: www.jsoftware.com
load 'math/calculus'
Newton =: adverb : ']-u%(u deriv_jcalculus_ 1)'(^:_)("0)
(^~ - +:) Newton 2
2
(^~ - +:) Newton 1
0 NB. Something wrong here!
]x=.(^~ - +:) Newton 0.2
0.346323
(x^x) = 2*x
1 NB. x= 0.346323 is Correct!
]x=.(^~ - +:) Newton 1.1
0.346323j1.2326e_32
(x^x)= 2*x
1 NB. This also works. (within tolerance limit)
Skip Cave
Cave Consulting LLC
On Thu, Feb 6, 2020 at 9:59 AM Henry Rich <henryhr...@gmail.com> wrote:
> 1. Choose a different starting guess
>
> 2. Update the addon
>
> Henry Rich
>
> On 2/6/2020 10:36 AM, Brian Schott wrote:
> > Henry et al,
> >
> > I have 2 questions.
> >
> > How would the second root at 2 be found with Skip's problem?
> > Why do I get the following error?
> >
> > server:~ brian$ /Users/brian/j901/bin/jconsole ; exit;
> > JVERSION
> > Engine: j901/j64avx/darwin
> > Release-c: commercial/2020-01-11T12:22:31
> > Library: 9.01.20
> > Platform: Darwin 64
> > Installer: J901 install
> > InstallPath: /users/brian/j901
> > Contact: www.jsoftware.com
> > load'math/calculus'
> > Newton =: adverb : ']-u%(u deriv_jcalculus_ 1)'(^:_)("0)
> > (^~ - +:) Newton 0.5
> > |domain error: deriv_jcalculus_
> > | 13!:8(3)
> >
> > Thanks,
> >
> > On Wed, Feb 5, 2020 at 7:34 AM Henry Rich <henryhr...@gmail.com> wrote:
> >
> >> I misread your function.
> >>
> >> (^~ - +:) Newton 1.1
> >> 0.346323j1.2326e_32
> >> (^~ - +:) Newton 0.5
> >> 0.346323
> >>
> >> Still need those guardrails!
> >>
> >> Henry Rich
> >>
> >> --
> > (B=)
> > ----------------------------------------------------------------------
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>
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