Hello Brian and others,
After finding the first root x1 you can deflate the original equation by
dividing it by (x-x1) .
Esa
load'math/calculus'
Newton =: adverb : ']-u%(u deriv_jcalculus_ 1)'(^:_)("0)
(+:-^~) Newton 0.5
0.346323
((+:-^~)%-&0.346323) Newton 1
2
-----Original Message-----
From: Programming <[email protected]> On Behalf Of Brian
Schott
Sent: Thursday, February 6, 2020 5:37 PM
To: Programming forum <[email protected]>
Subject: Re: [Jprogramming] Derivatives
Henry et al,
I have 2 questions.
How would the second root at 2 be found with Skip's problem?
Why do I get the following error?
server:~ brian$ /Users/brian/j901/bin/jconsole ; exit;
JVERSION
Engine: j901/j64avx/darwin
Release-c: commercial/2020-01-11T12:22:31
Library: 9.01.20
Platform: Darwin 64
Installer: J901 install
InstallPath: /users/brian/j901
Contact:
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load'math/calculus'
Newton =: adverb : ']-u%(u deriv_jcalculus_ 1)'(^:_)("0)
(^~ - +:) Newton 0.5
|domain error: deriv_jcalculus_
| 13!:8(3)
Thanks,
On Wed, Feb 5, 2020 at 7:34 AM Henry Rich <[email protected]> wrote:
> I misread your function.
>
> (^~ - +:) Newton 1.1
> 0.346323j1.2326e_32
> (^~ - +:) Newton 0.5
> 0.346323
>
> Still need those guardrails!
>
> Henry Rich
>
> --
(B=)
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