Here's another approach: ;/6?255#55
Here, I decided that "extended fifty times" really meant that you wanted another 50 copies of that expression (extended linearly). But of course you can tweak the numbers. FYI, -- Raul On Fri, Mar 13, 2020 at 12:49 AM Skip Cave <s...@caveconsulting.com> wrote: > > How can I generate the following result extended 50 times, without explicit > looping? > > (6?55);(6?55);(6?55);(6?55);(6?55) > > ┌───────────────┬───────────────┬─────────────────┬─────────────────┬───────────────┐ > > │13 4 19 43 3 52│10 1 4 46 52 11│38 12 48 50 54 45│36 54 39 35 53 50│44 1 7 > 54 11 41│ > > └───────────────┴───────────────┴─────────────────┴─────────────────┴───────────────┘ > > > > Skip Cave > Cave Consulting LLC > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
