Here's another approach:

   ;/6?255#55

Here, I decided that "extended fifty times" really meant that you
wanted another 50 copies of that expression (extended linearly). But
of course you can tweak the numbers.

FYI,

-- 
Raul

On Fri, Mar 13, 2020 at 12:49 AM Skip Cave <s...@caveconsulting.com> wrote:
>
> How can I generate the following result extended 50 times, without explicit
> looping?
>
> (6?55);(6?55);(6?55);(6?55);(6?55)
>
> ┌───────────────┬───────────────┬─────────────────┬─────────────────┬───────────────┐
>
> │13 4 19 43 3 52│10 1 4 46 52 11│38 12 48 50 54 45│36 54 39 35 53 50│44 1 7
> 54 11 41│
>
> └───────────────┴───────────────┴─────────────────┴─────────────────┴───────────────┘
>
>
>
> Skip Cave
> Cave Consulting LLC
> ----------------------------------------------------------------------
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