0j16":,.(100&*)4.57 4.34 4.44

457.0000000000000000

434.0000000000000000

444.0000000000000600

On Sat, May 16, 2020 at 12:34 AM 'Bo Jacoby' via Programming <
programm...@jsoftware.com> wrote:

>
>    (100&*)4.57 4.34 4.44
>
> 457 434 444
>
>    +./(100&*)4.57 4.34 4.44
> 2.63185e_11
>
>    (+./&.(100&*))4.57 4.34 4.44
> 2.63185e_13
>
>
>
> It doesn't work.
> Thanks.
> Bo.
>
>     Den fredag den 15. maj 2020 20.58.47 CEST skrev Hauke Rehr <
> hauke.r...@uni-jena.de>:
>
>  my 2¢
>
> the result is absolutely correct;
> both Henry Rich and Devon McCormick showed why
>
> If you’re dealing with values with two decimal places
> everywhere, either apply rounding after each operation,
> or (better imho) work on 100-fold values and divide by
> 100 in the very last step of your computation.
>
> you could also define your own data structure but then
> you’re better off using x: in the first place.
>
> Either you want to deal with rationals (x:) or with
> whole numbers (algorithm&.(100&*)).
>
>
> Am 15.05.20 um 17:20 schrieb 'Bo Jacoby' via Programming:
> >  The expression
> >     4.57+.(4.34+.4.44)
> >
> >
> > should evaluate like this
> >     4.34+.4.44
> > 0.02
> >
> >     4.57+.0.02
> > 0.01
> >
> >
> >
> > but it does evaluate to
> >      5.39568e_12
> >
> >
> > which is a useless and incorrect result.
> > =  is tolerant, why isn't   +.    ?
> > Thanks.
> > Bo.    Den fredag den 15. maj 2020 16.24.10 CEST skrev Henry Rich <
> henryhr...@gmail.com>:
> >
> >  What's wrong with it?
> >
> >     0j19 ": 4.57 4.34 4.44
> > 4.5700000000000002842 4.3399999999999998579 4.4400000000000003908
> >
> > Henry Rich
> >
> > On 5/15/2020 10:17 AM, 'Bo Jacoby' via Programming wrote:
> >>       +./4.57 4.34 4.44
> >> 5.39568e_12
> >>
> >> NB. this was not the correct answer.  A bug?
> >>
> >>       +./x:4.57 4.34 4.44
> >>
> >> 1r100
> >>
> >> NB. this was a work-around
> >> Thanks!
> >> Bo.
> >>
> >>
> >>
> >>
> >> ----------------------------------------------------------------------
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> >
> >
>
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