I can't answer that, but I can assure you that they do.
Henry Rich
On 1/16/2021 7:38 PM, bill lam wrote:
I didn't mean to change stdlib sooner or later, but if we do it again, rank
0 should be a better option.
Why users (beginner or not) would write a+"0 b or sin"0 ?
On Sun, Jan 17, 2021, 8:20 AM Henry Rich <[email protected]> wrote:
I would be happy for a user to do that, but changing stdlib might not be
a good idea. Beginning users often write
a +"0 b
and it doesn't cost them dearly. If you make the change, sin"0 will be
expensive.
Henry Rich
On 1/16/2021 7:17 PM, bill lam wrote:
Thanks. then defining sine as 1&o."0 should be fine.
On Sun, Jan 17, 2021, 8:07 AM Henry Rich <[email protected]> wrote:
What makes them efficient is IRS. 1&o. supports IRS; 1&o."0 does not.
Is you define sin as 1&o."0, sin will run fast, but sin"0 will not.
Henry Rich
On 1/16/2021 6:24 PM, bill lam wrote:
IIUC All atomic math functions are rank 0 but support IRS so that they
are
as efficient as rank infinity on long array arguments.
The question should be that
is 1&o."0 as efficient as 1&o. on long arrays.
On Sun, Jan 17, 2021, 12:32 AM Henry Rich <[email protected]>
wrote:
Terminology. If verb v has IRS, it can handle v"n internally without
a
rank loop.
+ has IRS. +"n does not need a rank loop.
+"n does not have IRS. +"n"n2 does need a rank loop.
+/@:*"1 has IRS, but +/@:* does not - that's how they're coded.
1&o."0 does not have IRS.
Henry Rich
On 1/16/2021 11:27 AM, bill lam wrote:
but the verb in this question is
(1&o.)"0
even if 1&o. has IRS, does (1&o.)"0 also has IRS ?
On Sun, Jan 17, 2021, 12:02 AM Henry Rich <[email protected]>
wrote:
m&v does have IRS if v does. I didn't know that until I just
checked.
Henry Rich
On 1/16/2021 7:10 AM, bill lam wrote:
I'm not sure if 1&o."0 has IRS (integrated rank support) or not. If
it
doesn't then I think the phase with infinity rank is fine.
On Sat, Jan 16, 2021, 7:02 PM Arnab Chakraborty <
[email protected]>
wrote:
Dear all,
Just wondering if the correct defn of sin shouldn't be
sin=:1&o."0
instead of
sin=:1&o.
which has rank infinity.
With the rank infinity definition +/@sin behaves just like +/@:sin
But, ideally, +/@sin 4 5 should be a list of two numbers, while
+/@:sin
should be their sum.
Just like, +/@*: and +/@:*:
Thanks and regards,
Arnab
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