Float is being used,
9!:11]16 sets 16 bit display
On 2021-05-04 11:22 p.m., Don Kelly wrote:+. 1 o. 1j1e_100
+. 1 o. 1j1e_11
0.8414709848078965 5.403023058681397e_12
+. 1 o. 1j1e_12
0.8414709848078965 5.403023058681398e_13
1 o. 1j1e_13
0.8414709848078965j5.403023058681398e_14
+. 1 o. 1j1e_14
0.8414709848078965 0 rounded off display and 1e_14 is close enough to
0 to be shown as 0
however
1 o. 1j1e13
0.8414709848078965j5.403023058681398e_14
1 o. 1j1e_14
0.8414709848078965 drops the 0 as there is only a single number as 1j0
is 1
in other word with a 16 digit display the result is rounded off at 16
digits even if the stored number was 32 or 64 or whatever.
( Just my opinion)
Don
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