The sequential machine is a very simple device.
When it emits a word, there's a starting index and an ending index and
it emits all of that subsequence.
The emit vector mechanism is a minor adjustment to emit word -- it
basically just changes the current ending index. It still includes the
entire subsequence.
If you want something different, that would be done either before or
after processing with this mechanism.
I hope this helps,
--
Raul
On Mon, Jan 16, 2023 at 7:01 AM Pawel Jakubas <jakubas.pa...@gmail.com> wrote:
>
> Hi Raul,
>
> I am not giving up on learning multiple words action. I have seen the
> example you referenced and try to use it on example we processed.
> M=: (a.=LF)+2*a.e.'0123456789'
> S=: +.".>cutLF {{)n
> 1j0 0j0 2j1 NB. start here
> 1j0 3j0 2j1 NB. other
> 1j5 3j5 2j0 NB. digit
> 1j0 4j1 2j1 NB. LF
> 1j3 3j0 2j2 NB. LF2
> }}
>
> test1=: {{)n
> 1000ddd
> 2000
>
> 1x
> x2
> }}
> (0;S;M;0 _1 0 _1) ;: test1
> ┌──────────────┬─┬─────┐
> │1000ddd 2000│ │1x x2│
> └──────────────┴─┴─────┘
> (5;S;M;0 _1 0 _1) ;: test1
> 0 _1 0 2 2 1 NB. 1
> 1 0 2 2 2 0 NB. 0
> 2 0 2 2 2 0 NB. 0
> 3 0 2 2 2 0 NB. 0
> 4 0 2 0 1 5 NB. d
> 5 _1 1 0 1 0 NB. d
> 6 _1 1 0 1 0 NB. d
> 7 _1 1 1 3 0 NB. LF
> 8 _1 3 0 1 0 NB. space
> 9 _1 1 0 1 0 NB. space
> 10 _1 1 2 2 1 NB. 2
> 11 10 2 2 2 0 NB. 0
> 12 10 2 2 2 0 NB. 0
> 13 10 2 2 2 0 NB. 0
> 14 10 2 1 3 5 NB. LF
> 15 _1 3 1 4 1 NB. LF
> 16 15 4 2 2 2 NB. 1
> 17 16 2 0 1 5 NB. x
> 18 _1 1 1 3 0 NB. LF
> 19 _1 3 0 1 0 NB. x
> 20 _1 1 2 2 1 NB. 2
> 21 20 2 1 3 5 NB. LF
>
> This is unexpected to me as I though to see
> ┌──────────────┬─┬─────┐
> │1000 2000 │1 2│
> └──────────────┴─┴─────┘
> For example, 5 action is invoked when in interaction number 4, so it should
> only include 0, 1, 2,3. In interaction number 4 j=_1 and ddd should not be
> included. Any hints what I am doing wrong?
>
> Thanks and best regards,
> Pawel
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