Henry Rich wrote:
> You need to take a little time out and learn about rank
> in J.

True, but perhaps not the immediate issue.

> ... but in either case I don't see why 'each' doesn't work:

I believe the issue was syntactic.

In J,
   X func each y
is equivalent to
   X (func each) y
and is NOT equivalent to
   X func (each y)

The latter is syntactically invalid, but someone applying
English grammar to J might expect differently.

-- 
Raul

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