I am not sure I understand right: <1 2 3 NB. "boxed vector of atoms" +-----+ |1 2 3| +-----+
Otherwise, if you have atoms to make a list, they don't need to be additionally boxed. 1,2,3 NB. list of atoms 1 2 3 a:,a:,a: NB. also list of atoms ++++ |||| ++++ ]X=: (1 2;3 4) NB. list of two boxed atoms +---+---+ |1 2|3 4| +---+---+ ]y=: <5 6 NB. a (scalar) boxed atom +---+ |5 6| +---+ X + each y +-----+-----+ |11 14|13 16| +-----+-----+ --- "Leigh J. Halliwell" <[EMAIL PROTECTED]> wrote: > Dear J Forum: > Let func be a dyadic function defined for atoms x and y. If Y is a boxed > vector of atoms, 'x func each Y' will do the function between x and each > atom of Y (i.e., one with many). And if X is a boxed vector of as many > atoms, 'X func Y' will do the function between corresponding atoms of X and > Y (i.e., many with many). But how can I do the many-to-one case, 'X func > y'? The adverb "each" doesn't like the left argument. > Sincerely, > Leigh __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
