Hello, I am not sure if I understand the '~' (reflex) adverb right.
1) Is the following true? (f~ @: g)y is the same as (gy) f (gy). 2) Now, I want to pass the parameter y to the function f before it is applied. Is that possible? Regards, Yuva Example: (absolute beginner exploration...optimal versions are welcome!) NB. create a n by n matrix with 0 to (n-1) repeated n times n =. 3 NB. solution1: ravel the laminations n-1 times (,: i.n) ,^: (<:n) (,: i.n) 0 1 2 0 1 2 0 1 2 NB. hmmm... looks like the n can be factored out... NB. I see a reflex form, and then a power.... NB. so, sol1 =: (,^: (<:])~) @: (,: i.) $ sol1 n 2 3 4 3 NB. Oops! The n has not reached the inner function. Is the form right?? NB. Another way using transpose.... sol2 =. |: @: (#"0 i.)~ sol2 n NB. works as intended 0 1 2 0 1 2 0 1 2 ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
