Leigh J. Halliwell wrote:
> (i.0) (4 : '(,y~:0) expand x<;.1~;y{. each 1') 0 0 0
> 0 0 0
>
> I would like it in this case to be three empty boxes. Can I make the expand
> operator fill with empty boxes?
>
First I found any nonempty left argument will give 3 empty boxes.
btw, would it be more intuitive if swap left and right arguments.
('a') (4 : '(,y~:0) expand x<;.1~;y{. each 1') 0 0 0
and #^:_1 seems do not like fit conjunction.
1 1j2 1 #!.9 [4 5 6
4 5 9 9 6
1 1 0 0 1 (#!.9)^:_1 [4 5 6
|domain error
| 1 1 0 0 1 #(!.9)^:_1[4 5 6
1 1 0 0 1 (#^:_1)(!.9) [4 5 6
|domain error
| 1 1 0 0 1 (#^:_1)(!.9)[4 5 6
could anyone suggest a phrase to convert left argument to #^:_1 to the format
required by # so that there will be a workaround to #^:_1 ?
1 1 0 0 1 => 1 1j2 1
--
regards,
bill
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