John;
Okay, I see a different idea. Thanks for the clarification. Now I'll go
solve it.
John Randall wrote:
R.A. MacDonald wrote:
Perhaps a rephrase: I get the same number of occurrences of drawing an
A5 sheet from the container/pile/bucket: 8. Of course, I understand
that one ends up with 16 A5's at the end.
Randy:
This is not the problem: you need the expected value of the number of
trials, excluding the first and last, in which the number of sheets (of
any size, not just A5) is 1.
Best wishes,
John
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