On 7/17/07, Randy MacDonald <[EMAIL PROTECTED]> wrote:
I was wondering how to explain ]t =:;: ^:_1 s =: 'string' s t r i n g since s is not the same as ;: t
As I understand it, (;:^:_1) produces the same result as ([: ;@}: 1j1 #!.(<' ') ::(#!.' ') ]) -- Raul ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
