Hello Roger;
n =: >: 1505 % a
If this has been noted, my apologies: I'm doing Xmas catchup.
Roger Hui wrote:
The calculation of n was off by 1, and the correction is as follows:
a=: 215 275 335 355 420 580
n=: 1 + <.1505 % a
b=: 1505 = ((#: i.@(*/)) n) +/ .* a
n #: I. b
1 0 0 2 0 1
7 0 0 0 0 0
(n #: I. b) +/ .* a
1505 1505
----- Original Message -----
From: Roger Hui <[EMAIL PROTECTED]>
Date: Friday, December 21, 2007 13:43
Subject: Re: [Jprogramming] Not so hard to solve the comic in J?
To: Programming forum <[email protected]>
a=: 215 275 335 355 420 580
n=: <.1505 % a
b=: 1505 = ((#: i.@(*/)) n) +/ .* a
n #: I. b
1 0 0 2 0 1
1 0 0 2 0 1 +/ .* a
1505
----- Original Message -----
From: Devon McCormick <[EMAIL PROTECTED]>
Date: Friday, December 21, 2007 13:32
Subject: [Jprogramming] Not so hard to solve the comic in J?
To: J-programming forum <[email protected]>
How hard is it to solve this problem? http://xkcd.com/287/
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|\ | | The only real problem with APL is that
BSc(Math) UNBF'83 | it is "still ahead of its time."
Sapere Aude | - Morten Kromberg
Natural Born APL'er |
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