Sorry, typo. If k does not exactly divide 1505, the needed numbers are again 0 1 2 ... <.1505%k , in other words i.1+<.1505%k
----- Original Message ----- From: Roger Hui <[EMAIL PROTECTED]> Date: Sunday, January 6, 2008 20:36 Subject: Re: [Jprogramming] Not so hard to solve the comic in J? To: Programming forum <[email protected]> > No, the expression has to be 1+<.1505%a . > > Let k be an element of a. If k exactly divides 1505 > with a quotient of q, the needed numbers are > 0 1 2 ... q , in other words i.1+q, in other words > i.1+<.1505%k . If k does not exactly divide 1505, > the needed numbers are again 0 1 2 ... 1+<.1505%k . > > > > ----- Original Message ----- > From: Randy MacDonald <[EMAIL PROTECTED]> > Date: Sunday, January 6, 2008 20:04 > Subject: Re: [Jprogramming] Not so hard to solve the comic in J? > To: Programming forum <[email protected]> > > > Sorry, > > > > >. 1505 % a > > > > Too easy to make a spelling mistake, especially a 1-pixel one. > > > > Roger Hui wrote: > > > But > > > >: 1505 % a > > > 8 6.47273 5.49254 5.23944 4.58333 3.59483 > > > > > > and non-integers would lead to errors in later expressions. > > > > > > > > > > > > ----- Original Message ----- > > > From: Randy MacDonald <[EMAIL PROTECTED]> > > > Date: Friday, January 4, 2008 12:10 > > > Subject: Re: [Jprogramming] Not so hard to solve the comic > in J? > > > To: Programming forum <[email protected]> > > > > > > > > >> Hello Roger; > > >> > > >> n =: >: 1505 % a > > >> > > >> If this has been noted, my apologies: I'm doing Xmas catchup. > > >> > > >> Roger Hui wrote: > > >> > > >>> The calculation of n was off by 1, and the correction is > as > > follows:>>> > > >>> a=: 215 275 335 355 420 580 > > >>> n=: 1 + <.1505 % a > > >>> b=: 1505 = ((#: i.@(*/)) n) +/ .* a > > >>> n #: I. b > > >>> 1 0 0 2 0 1 > > >>> 7 0 0 0 0 0 > > >>> (n #: I. b) +/ .* a > > >>> 1505 1505 > > >>> > > >>> > > >>> > > >>> ----- Original Message ----- > > >>> From: Roger Hui <[EMAIL PROTECTED]> > > >>> Date: Friday, December 21, 2007 13:43 > > >>> Subject: Re: [Jprogramming] Not so hard to solve the comic > > in J? > > >>> To: Programming forum <[email protected]> > > >>> > > >>> > > >>> > > >>>> a=: 215 275 335 355 420 580 > > >>>> n=: <.1505 % a > > >>>> b=: 1505 = ((#: i.@(*/)) n) +/ .* a > > >>>> n #: I. b > > >>>> 1 0 0 2 0 1 > > >>>> 1 0 0 2 0 1 +/ .* a > > >>>> 1505 > > >>>> > > >>>> > > >>>> > > >>>> ----- Original Message ----- > > >>>> From: Devon McCormick <[EMAIL PROTECTED]> > > >>>> Date: Friday, December 21, 2007 13:32 > > >>>> Subject: [Jprogramming] Not so hard to solve the comic in J? > > >>>> To: J-programming forum <[email protected]> > > >>>> > > >>>> > > >>>> > > >>>>> How hard is it to solve this problem? > http://xkcd.com/287/ ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
