ls,
I heard of the following problem from a friend.
Given:
f(x) = x - f(f(x-1))
f(0) = 1

I can compute f(1) = 1 - f(f(1-1)) = 1 - f(f(0)) = 1 - f(1) <=> f(1) = 1
- f(1) <=> 2f(1) = 1 <=> f(1) = 1/2. But this does not help much: f(2) =
2 - f(f(2-1)) = 2 - f(f(1)) = 2 - f(1/2).

Questions:
1. Do functions f exists on R -> R that are continuous?
2. Can J help him with the question? Could memoization help?

Thanks for any help.
Jan.

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