Jacobs, Jan wrote: > 1. Do functions f exists on R -> R that are continuous?
Here is an idea as to how to approach this. Let g:[0,1]->[0,1] be an arbitrary continuous function with g(0)=1, g(1)=1/2. Define f=g on [0,1]. Now extend f to (1,2] by using f(1+x)=1+x - f f(x)=1+x - f g(x)=1+ x - g g(x), since x is in (0,1]. Keep going. Best iwhses, John ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
